What is the sin(theta) in a right triangle given the value below?

cos0=3/5

If you sketch your triangle,

sinθ = opposite/hypotenuse = 3/5
so you are missing the adjacent, commonly referred to the x
x^2 + 3^2 = 5^2
x^2 = 25-9 = 16
x = √16 = 4
Notice you have the most basic Pythagorean triangle with sides
3, 4, and 5
then cosθ = adjacent/hypotenuse = 4/5