A particle is projected at 20 m/s in a direction 15 degrees above the horizontal.
a) what is the maximum height the particle reaches? note: at maximum height the particle will have zero velocity in the vertical direction.
b) what is the horizontal distance that the particle has travelled when it reaches its maximum height? below is a diagram of the path that the particle makes.
h = v^2/(2g) sin^2θ
R = v^2/(2g) sin2θ