A solution of sodium carbonate reacts with sulphuric acid. What is the ionic equation?
THE MOLECULAR EQUATION IS:
2NaOH(aq) + H2SO4(aq) ==> Na2SO4(aq) + 2H2O(l)
THE IONIC EQUATION IS:
2Na^+(aq) + 2OH^-(aq) + 2H^+(aq) + SO4^2-(aq) ==> 2Na^+(aq) + SO4^2-(aq) + 2H2O(l)
THE NET IONIC EQUATION IS:
2H^+(aq) + 2OH^-(aq) ==> 2H2O(l)
To write the ionic equation for the reaction between sodium carbonate (Na2CO3) and sulfuric acid (H2SO4), we need to identify the ions involved in the reaction.
The ionic equation is a way to represent a chemical reaction by showing the dissociated ions separately.
First, let's identify the ions:
Sodium carbonate (Na2CO3) dissociates into two sodium ions (Na+) and one carbonate ion (CO32-).
Sulfuric acid (H2SO4) dissociates into two hydrogen ions (H+) and one sulfate ion (SO42-).
Now, let's write the balanced molecular equation for the reaction:
Na2CO3 + H2SO4 -> Na2SO4 + H2O + CO2
Next, let's write the ionic equation by showing the dissociated ions:
2Na+ + CO32- + 2H+ + SO42- -> 2Na+ + SO42- + H2O + CO2
Finally, we can cancel out the spectator ions (those appearing on both sides of the equation) to get the simplified ionic equation:
CO32- + 2H+ -> H2O + CO2
So, the ionic equation for the reaction between sodium carbonate (Na2CO3) and sulfuric acid (H2SO4) is:
CO32- + 2H+ -> H2O + CO2
To determine the ionic equation for the reaction between sodium carbonate and sulfuric acid, we first need to know the chemical formulas of these compounds.
The chemical formula for sodium carbonate is Na2CO3, and it completely dissociates in water to form sodium ions (Na+) and carbonate ions (CO3^2-).
Sulfuric acid, on the other hand, is represented by the formula H2SO4. When it dissolves in water, it dissociates to produce hydrogen ions (H+) and sulfate ions (SO4^2-).
Now, let's write the balanced chemical equation for the reaction between sodium carbonate and sulfuric acid:
Na2CO3 + H2SO4 -> Na2SO4 + H2O + CO2
From this balanced equation, we can now write the ionic equation by writing out the ions involved in the reaction:
2Na+ + CO3^2- + 2H+ + SO4^2- -> 2Na+ + SO4^2- + H2O + CO2
Simplifying the equation by canceling out the common ions gives us the final ionic equation:
2H+ + CO3^2- -> H2O + CO2
Therefore, the ionic equation for the reaction between sodium carbonate and sulfuric acid is 2H+ + CO3^2- -> H2O + CO2.