Three consecutive terms of an AP .half the sum of -12 and product-48 find the numbers
(n-d) + n + (n+d) = -12
(n-d)n ( n+d) = -48
3 n = -12
n = -4
(-4-d) (-4)(-4+d) = -48
16 -d^2 = 12
d^2 = 4
try d = 2
-6 , -4 , 2
(n-d)n ( n+d) = -48
3 n = -12
n = -4
(-4-d) (-4)(-4+d) = -48
16 -d^2 = 12
d^2 = 4
try d = 2
-6 , -4 , 2