Aforce Of 4oN Is Used To Stretch Aspring Which Has Aspring Constant 350 N/m.How Much Energy Is Stored In The Spring?

F = kx

so x = 40/350 = 4/35
E = 1/2 kx^2 = 1/2 (350) (4/35)^2 = ____ J

Habtamu

f = 40 N

k=350m/s
x=?
so f=kx
x=f/k
x=40/350
x=0.11

The displacement of the spring is 0.11 meters.

The energy stored in the spring can be calculated as:

E = 1/2 kx^2

E = 1/2 (350 N/m) (0.11 m)^2

E = 2.0275 Joules

Therefore, the energy stored in the spring is 2.0275 J (Joules).

Well, the spring seems to be stretching to meet its full potential! Let's calculate the energy stored in it using Hooke's law and a pinch of humor.

The formula for calculating the potential energy stored in a spring is given by:

E = (1/2) kx^2

Where E is the energy stored, k is the spring constant, and x is the displacement from the equilibrium position.

Now, rearranging the equation, we have:

E = (1/2) kx^2

Plugging in the values provided, we get:

E = (1/2) * 350 N/m * (0.04 m)^2

Calculating that out, we find:

E ≈ 0.28 Joules

So, the spring is springing with an energy of approximately 0.28 Joules! That's enough energy to make a clown bounce around with joy (or a pie fly across the room)!

Hope that brings a spring to your step!

To calculate the energy stored in the spring, we can use Hooke's law and the formula for potential energy.

Hooke's law states that the force applied to a spring is directly proportional to the distance it is stretched or compressed. Mathematically, it can be expressed as:

F = k * x

Where:
F is the force applied to the spring (40 N in this case)
k is the spring constant (350 N/m in this case)
x is the displacement or stretch of the spring from its equilibrium position

Rearranging the equation, we can solve for x:

x = F / k

Substituting the given values:

x = 40 N / 350 N/m

x = 0.1143 m

The potential energy stored in a spring is given by the formula:

PE = (1/2) * k * x^2

Substituting the values we found earlier:

PE = (1/2) * 350 N/m * (0.1143 m)^2

PE ≈ 2.01 J

Therefore, the energy stored in the spring is approximately 2.01 Joules.

A force of 40 N is used to stretch a spring constant of 350 N/n.

How much energy is stored in the spring