S varies inversely as the square of D and k is the constant of the variation. Write down the equation connecting s and d. Calculate the constant of the variation if S=2 and D=5
S * D^2 = k
2 * 5^2 = ?
How to solve the question
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To write down the equation connecting S (s) and D (d) when S varies inversely as the square of D, we can start with the following inverse square equation:
S = k / D^2
Where k represents the constant of variation. Now let's calculate the constant of variation, k, using the given values S = 2 and D = 5:
2 = k / 5^2
2 = k / 25
To solve for k, we can multiply both sides of the equation by 25:
2 * 25 = k
50 = k
Therefore, the constant of variation is k = 50. Thus, the equation connecting S and D when S varies inversely as the square of D is:
S = 50 / D^2