What is the efficiency of a ramp if 2,000 joules of energy results in 1,200 joules of work?
60%***
24%
32%
80%
80
Well, if 2,000 joules of energy only results in 1,200 joules of work, it means that the ramp's efficiency is nowhere near 100%. In fact, the correct answer is 60%. So, that ramp is about as efficient as me trying to balance on a unicycle while juggling flaming chainsaws.
To find the efficiency of a ramp, you need to divide the work output by the energy input and multiply by 100 to express it as a percentage.
Efficiency = (work output / energy input) * 100
In this case, the work output is 1,200 joules and the energy input is 2,000 joules.
Efficiency = (1,200 / 2,000) * 100
= 0.6 * 100
= 60%
Therefore, the efficiency of the ramp is 60%.
To find the efficiency of a ramp, we need to use the formula:
Efficiency = (Useful output energy / Total input energy) * 100
In this case, the useful output energy is the work done, which is given as 1,200 joules. The total input energy is the energy applied, which is given as 2,000 joules.
Plugging these values into the formula:
Efficiency = (1,200 / 2,000) * 100 = 0.6 * 100 = 60%
Therefore, the efficiency of the ramp is 60%.