how much potassium chlorate would dissolve kin 200g water at 20°C
The molar mass of potassium chlorite is (39.10)+ 35.45+(16×3) = 122.55 g/mol
The molar mass of water is 16+(1×2) = 18g/mol
the reaction between water and potassium chlorite is
KClO3 + H2O ——› H2+ KClO4
Basically, 122.55 grams of potassium chlorate dissolved in 18 grams of water is the same as 1 gram of potassium chlorite dissolved in 18/122.55 grams of water. Or, we can say that 18 grams of water are required to dissolve 122.55 grams of potassium chlorate and 1 gram of water is required to dissolve 122.5/18 grams of potassium chlorate
so 200 grams of water is required to dissolve (200×122.5)/18 gm of potassium chlorite = 1361.1 gm at 20°C
@ AJ L. I don't believe anything you wrote. First there is no reaction between KClO3 and H2O that comes close to what you wrote. Second, it is not a stoichiometric problem. Third KClO3 is potassium chlorATE and not chlorITE. Potassium chlorite would be KClO2.
@Immmm-- You need to look up and tell us what the solubility of KClO3 is per 100 g H2O or per 100 mL H2O. I expect that is in your question or your notes/text book.
To determine how much potassium chlorate would dissolve in 200g of water at 20°C, we can consult the solubility chart for potassium chlorate. The solubility of a compound is typically given in grams of solute per 100 grams of solvent (usually water).
Unfortunately, the solubility of potassium chlorate at 20°C is not readily available in this format. However, we can make an approximation by considering the solubility at a different temperature and using a common solubility trend.
Let's assume that at 20°C, the solubility of potassium chlorate is similar to that at 25°C, which is approximately 20 grams per 100 grams of water.
Now we have to determine the solubility in 200 grams of water. We can set up a proportion to find the amount of potassium chlorate that would dissolve in 200 grams of water.
(20g / 100g) = (xg / 200g)
Using cross-products, we can solve for x:
20g * 200g = 100g * xg
4000g = 100g * xg
Dividing both sides by 100g:
4000g / 100g = xg
40g = xg
Therefore, approximately 40 grams of potassium chlorate would dissolve in 200 grams of water at 20°C, assuming the solubility at 25°C can be extrapolated to 20°C.