A baket of mass 2.5kg is shot and move with a velocity of 30ms calcute the kinetic energy of bullet
my answer
not sure what a "baket" is, but
KE = 1/2 mv^2
so plug in your numbers
To calculate the kinetic energy of an object, you need to use the equation:
Kinetic Energy = 1/2 * Mass * Velocity^2
Given:
Mass (m) of the bullet = 2.5 kg
Velocity (v) of the bullet = 30 m/s
Now, we can plug these values into the formula:
Kinetic Energy = 1/2 * 2.5 kg * (30 m/s)^2
First, we square the velocity:
Kinetic Energy = 1/2 * 2.5 kg * 900 m^2/s^2
Next, we multiply the mass by the squared velocity:
Kinetic Energy = 1/2 * 2.5 * 900 kg * m^2/s^2
Now, we can perform the multiplication:
Kinetic Energy = 1125 kg * m^2/s^2
Finally, we simplify the units to get the final answer:
Kinetic Energy = 1125 Joules (J)
Therefore, the kinetic energy of the bullet is 1125 J.