a body accelerated uniformly from rest at 2m/s calculate it velocity after travelling 9m
Do you mean a = 2 m/s^2 ???
if so
then
v = Vi + a t = 0 + 2 t
d = Vi t + (1/2) a t^2 = 0 + t^2
9 = t^2
t = 3 seconds
I want to improve my grades
To calculate the velocity of a body that is accelerated uniformly, we can use the following formula:
V = √(2as)
Where:
V is the final velocity,
a is the acceleration, and
s is the distance traveled.
In this case, the body is accelerated uniformly from rest, which means its initial velocity (u) is 0 m/s.
Given:
u = 0 m/s (initial velocity)
a = 2 m/s² (acceleration)
s = 9 m (distance traveled)
Using the formula, we can find the final velocity (V):
V = √(2as)
V = √(2 * 2 * 9)
V = √36
V = 6 m/s
Therefore, the velocity of the body after traveling 9 meters is 6 m/s.