Findbin the simplest form the ratio between the perimeter of the triangle whose side lengths are 6cm ,8cm and 10cm. And the perimeter of the rhombus whose side length is 0.15m.
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perimeter of triangle = 6+8+10 cm = 24 cm
perimeter of rhombus = 4(.14)m = 4(14)cm = 56 cm
perimeter of triangle : perimeter of rhombus = 24 : 56
= 3 : 7
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To find the ratio between the perimeter of the triangle and the perimeter of the rhombus, you need to calculate the two perimeters separately and then divide them.
First, let's find the perimeter of the triangle. The perimeter of a triangle is the sum of its side lengths. In this case, the side lengths are given as 6cm, 8cm, and 10cm. So the perimeter of the triangle is:
Perimeter of triangle = 6cm + 8cm + 10cm = 24cm.
Next, let's find the perimeter of the rhombus. A rhombus has four equal side lengths, given as 0.15m. To calculate the perimeter, we multiply the side length by 4:
Perimeter of rhombus = 0.15m * 4 = 0.6m.
Now that we have both perimeters, we can find the ratio by dividing the perimeter of the triangle by the perimeter of the rhombus:
Ratio = Perimeter of triangle / Perimeter of rhombus
= 24cm / 0.6m.
Before we can divide, we need to convert the units to be the same. We can convert cm to meters by dividing by 100 (as there are 100 cm in 1 m):
24cm = 24cm / 100 = 0.24m.
Now we can divide the perimeters:
Ratio = 0.24m / 0.6m = 0.4.
Therefore, the ratio between the perimeter of the triangle and the perimeter of the rhombus is 0.4.