Students filled 6 rows in Level 1 of Section A and 3 rows in Level 3 of Section B.
How many students were seated in the auditorium?
Number of Seats Per Row in the Auditorium
Section Level 1 Level 2 Level 3
A 9 12 14
B 12 16 18
6*9 + 3*18 = 54 + 54 = 108
Students filled 6 rows in Level 1 of Section A and 3 rows in Level 3 of Section B.
How many students were seated in the auditorium?
Well, it looks like Section A has 6 rows in Level 1 and Section B has 3 rows in Level 3.
Let's calculate how many students were seated in each section:
For Section A, Level 1:
6 rows * 9 seats/row = 54 students
For Section B, Level 3:
3 rows * 18 seats/row = 54 students
So, if we add the number of students seated in each section together, we get:
54 students + 54 students = 108 students in total.
Therefore, there were 108 students seated in the auditorium.
To find the answer, we need to determine the number of students seated in Level 1 of Section A and Level 3 of Section B, and then add them together.
For Level 1 of Section A:
Number of rows filled: 6
Number of seats per row: 9
Total number of seats filled in Level 1 of Section A: 6 * 9 = 54 students
For Level 3 of Section B:
Number of rows filled: 3
Number of seats per row: 18
Total number of seats filled in Level 3 of Section B: 3 * 18 = 54 students
Now let's add the number of students in Level 1 of Section A and Level 3 of Section B:
54 + 54 = 108
Therefore, there were 108 students seated in the auditorium.
Students filled 6 rows in Level 1 of Section A and 3 rows in Level 3 of Section B.
How many students were seated in the auditorium?
Math