A(-4, 3) maps to A'(0, 1) through a translation. Which rule describes the translation?
0 = -4+4
1 = 3-2
so, (x,y) → (x+4,y-2)
Well, this translation seems to have gone all the way from -4 to 0 on the x-axis, and from 3 to 1 on the y-axis. It must be the rule of "No Parking: Moving from Negativeville to Zero Town!"
To find the rule that describes the translation, we need to determine how the x-coordinate and y-coordinate of point A are translated to obtain point A'.
Let's first look at the change in the x-coordinate. The x-coordinate of A' is 0, while the x-coordinate of A is -4.
To go from -4 to 0, we need to add 4. So the translation moves the x-coordinate of A 4 units to the right.
Now let's consider the change in the y-coordinate. The y-coordinate of A' is 1, while the y-coordinate of A is 3.
To go from 3 to 1, we need to subtract 2. So the translation moves the y-coordinate of A 2 units down.
Putting it all together, the translation moves the x-coordinate 4 units to the right and the y-coordinate 2 units down.
Therefore, the rule that describes the translation is: (x, y) -> (x + 4, y - 2).
To determine the rule that describes the translation from point A(-4, 3) to A'(0, 1), we need to find the horizontal and vertical shifts.
The horizontal shift represents the change in the x-coordinate, while the vertical shift represents the change in the y-coordinate.
To find the horizontal shift, we subtract the x-coordinate of A from the x-coordinate of A':
Horizontal shift = x-coordinate of A' - x-coordinate of A
Horizontal shift = 0 - (-4)
Horizontal shift = 4
Therefore, the horizontal shift is 4 units to the right.
To find the vertical shift, we subtract the y-coordinate of A from the y-coordinate of A':
Vertical shift = y-coordinate of A' - y-coordinate of A
Vertical shift = 1 - 3
Vertical shift = -2
Therefore, the vertical shift is 2 units downwards.
The rule that describes the translation is:
Move 4 units to the right and 2 units downwards.