Andy and Sally had $384 altogether. Andy had $8 more than Sally. Andy
spent twice as much as Sally and was left with half as much as Sally. How
much money did Sally spend?
$384 - 3×$8 = $360
$376=(3+3) = $60
560 + 58 = $68
sally had x
Andy had x+8
x + x+8 = 384
x = 188
So at the start Sally had $188 and Any had $196
amount spent by Sally --- y
amount spent by Andy --- 2y
amount left by Andy = 196-2y
amount left by Sally = 188-y
196-2y = (1/2)(188-y)
392 - 4y = 188 - y
-3y = -204
y = 68
so Sally spent $68
To find out how much money Sally spent, we can use algebra. Let's let "x" represent the amount of money Sally had.
According to the problem, Andy had $8 more than Sally, so Andy had (x + $8) dollars.
Andy spent twice as much as Sally, so he spent 2x dollars.
After spending, Andy was left with half as much as Sally, so Andy had (1/2)x dollars remaining.
Since Andy and Sally had $384 altogether, we can set up the equation: 2x + (1/2)x + x + $8 = $384.
Combining like terms, we get: (5/2)x + $8 = $384.
Next, we subtract $8 from both sides of the equation: (5/2)x = $376.
To solve for x, we multiply both sides of the equation by 2/5: x = ($376)(2/5).
Simplifying, we find that x = $150.40.
Therefore, Sally had $150.40.
Since Sally spent a certain amount of money, we don't have enough information to determine exactly how much she spent.