A man pushes a box , initially at rest towards another man by exerting a constant horizontal
force of magnitude 5N through a distance of 1m. Its kinetic energy is ?
5
work done = force * distance
all that work is now KE
Well, if the man is pushing a box towards another man, I hope there's a good reason for it. Maybe they're playing a game of "Who Can Push This Box the Farthest?" or they're just really passionate about moving boxes.
Anyway, let's talk about the kinetic energy of the box. The formula for kinetic energy is K.E. = 1/2 * mass * velocity^2. Since the box starts at rest, its initial velocity is zero.
To find the final velocity, we can use the equation F = m * a, where F is the force exerted by the man and m is the mass of the box. Since the force is constant and applied horizontally, we can rearrange the equation to find the acceleration: a = F / m.
But wait a minute, we don't know the mass of the box! Without that information, we can't calculate the final velocity or the kinetic energy.
So, my friend, it looks like we need more details to solve this puzzle. In the meantime, maybe those two men should consider starting a box-pushing Olympics or something. It could be a real crowd-pleaser!
To find the kinetic energy of the box being pushed, we need to know its mass and its velocity. However, without this information, we cannot directly calculate the kinetic energy.
Kinetic energy (KE) can be calculated using the formula: KE = (1/2)mv^2, where m is the mass of the object and v is its velocity.
To calculate the velocity, we can use the formula for average velocity: v = d/t, where d is the displacement (distance) and t is the time taken.
In this scenario, we are given the distance the box is pushed (1m), but we do not have the time or the mass.
If we assume that the box is pushed with a constant force of 5N, we can use Newton's second law (F = ma) and the definition of acceleration (a = Δv/Δt) to find the acceleration of the box.
Since the force is constant, we can use F = ma to find the acceleration: 5N = ma.
If we assume the mass is 1kg (since it is not specified), then the acceleration would be 5 m/s^2.
Next, we need the time taken to travel the distance of 1m. Using the equation of motion: d = (1/2)at^2, where d is the displacement, a is the acceleration, and t is the time taken.
Rearranging the equation to solve for time: t = √(2d/a), we substitute the values: t = √(2*1/5) ≈ 0.632 seconds.
Now that we have the time taken and the distance, we can calculate the average velocity: v = d/t = 1m/0.632s ≈ 1.58 m/s.
Finally, with the velocity and by assuming the mass is 1kg, we can find the kinetic energy. Therefore, KE = (1/2)mv^2 = (1/2)*1kg*(1.58 m/s)^2 ≈ 1.98 Joules.
Hence, the kinetic energy of the box being pushed is approximately 1.98 Joules.