using a ruler a pair of compass only construct (1)triangle abc with [ab]=10cm,angle abc=30° and angle bac=45°
i want the answer
draw AB
I assume you can construct a 60° angle
bisect it to get 30°
bisect a 30° angle and add it to 30° to get 45°
At A draw the 45° angle
At B draw the 30° angle
where those two rays intersect is C
To construct triangle ABC with [AB] = 10cm, ∠ABC = 30°, and ∠BAC = 45°, follow these steps:
1. Draw a line segment AB of length 10cm using a ruler. Label the endpoints A and B.
2. Place the pointed end of the compass at point A and draw an arc that intersects line AB.
3. Without changing the compass width, place the pointed end at point B and draw another arc that intersects the previous arc you drew. Label this point of intersection as C.
4. Using a ruler, draw a line segment AC to connect points A and C.
5. Using a ruler, draw a line segment BC to connect points B and C.
6. Measure the angle ∠ABC using a protractor and check that it measures 30°.
7. Measure the angle ∠BAC using a protractor and check that it measures 45°.
You have now constructed triangle ABC with [AB] = 10cm, ∠ABC = 30°, and ∠BAC = 45° using only a ruler and pair of compass.
To construct a triangle ABC with AB measuring 10 cm, angle ABC measuring 30°, and angle BAC measuring 45° using only a ruler and a pair of compass, follow these steps:
Step 1: Draw a line AB of length 10 cm using the ruler.
Step 2: From point A, draw an arc with any radius greater than half the length of AB using the compass. This arc should intersect AB.
Step 3: Without changing the compass width, place the compass on point B and draw another arc, intersecting the previous arc. Let's call this point C.
Step 4: With point A as the center, draw an arc that intersects line AB and intersects one of the arcs at point D.
Step 5: Using point D as the center, draw an arc that intersects line AB and intersects the other arc at point E.
Step 6: Draw a line from point E to point B and extend it past B. Let's call this line BF.
Step 7: Using point B as the center, draw an arc with the same radius intersecting line BF. Call this intersection point G.
Step 8: With point G as the center, draw an arc that intersects the arc drawn from point D. Let's call this point H.
Step 9: Draw a line from point H to point A.
Now, triangle ABC is constructed with AB measuring 10 cm, angle ABC measuring 30°, and angle BAC measuring 45°.