During a baseball game, a batter hits a high-pop. If the ball remains in the air for 6.0s, how high does it rise?
To determine how high the ball rises during a high-pop in a baseball game, we can use the equations of motion.
Here's how you can calculate the height:
1. Identify the necessary information:
- Time: Given as 6.0 seconds (the time the ball remains in the air).
- Acceleration Due to Gravity: Approximately 9.8 m/s² (assuming no air resistance).
2. Select the appropriate equation:
The equation we will use is:
height = (initial velocity * time) - (0.5 * acceleration * time²)
Since we do not have the initial velocity, we need additional information to solve for the height.
3. Find the initial velocity using another equation:
The equation to find the initial velocity is:
vertical velocity = acceleration * time
Here, we know the acceleration due to gravity (9.8 m/s²) and the time (6.0 seconds). Calculate the vertical velocity using this equation.
4. Substitute the obtained initial velocity into the height equation:
Now that we have the initial velocity, we can substitute it back into the height equation:
height = (vertical velocity * time) - (0.5 * acceleration * time²)
Plug in the values and calculate the height.
Please note that these calculations assume no external factors like air resistance, spin, or wind affecting the trajectory of the ball.