you want to mat and frame a 5 x 7 photograph. The perimeter of the outside of the mat is 44 inches. The mat is twice as wide at the top and bottom as it is at the sides. Find the dimensions of the mat.
Draw a diagram. You can see that
2(5+2x + 7+4x) = 44
solve for x and then finish it off
Bot
Which style of English is a formal or conventional way of expressing ideas to an audience?(1 point)
A. speech
B. standard
C. jargon
D. informal
B. Standard
Use the sentence to answer the question.
I couldn't hardly hear the teacher because the other students were making too much noise.
Which aspect of the sentence shows evidence of informal language?
A. slang
B. intensive pronoun
C. sentence structure
D. double negative
D. Double negative.
To find the dimensions of the mat, let's assign variables to the width of the mat at the sides and the width of the mat at the top and bottom.
Let's say the width of the mat at the sides is "x".
Since the mat is twice as wide at the top and bottom, the width at the top and bottom would be "2x".
Next, we can calculate the length and width of the photo according to the provided dimensions. The length is 7 inches, and the width is 5 inches.
The overall perimeter of the mat is given as 44 inches. The formula for the perimeter of a rectangle is 2(length + width). In this case, the length of the mat would be the length of the photo plus twice the width of the mat at the top and bottom (2x). The width of the mat would be the width of the photo plus twice the width of the mat at the sides (2x).
Using the formula and the given information, we can write the equation:
2((7 + 2x) + (5 + 2x)) = 44
Now, we can solve this equation to find the value of "x" and determine the dimensions of the mat.
2(7 + 2x + 5 + 2x) = 44
2(12 + 4x) = 44
24 + 8x = 44
8x = 44 - 24
8x = 20
x = 20 / 8
x = 2.5
Therefore, the width of the mat at the sides (x) is 2.5 inches, and the width of the mat at the top and bottom (2x) is 2.5 * 2 = 5 inches.
So, the dimensions of the mat are 2.5 inches (sides) by 5 inches (top and bottom).