IF THE 6TH TERM OF AN A.P IS 11, AND THE FIRST TERM IS 1. FIND THE COMMON DIFFERENCE?
Tn = a + (n-1)d
1 = a + (1-1)d = a
11 =a + 5 d = 1 + 5 d
d =10/5 = 2
How did you have 10
5+5
TN=a+(n-1)d
1=a+(1-1)d=a
11=a+5d=1+5d
d=A10/5=2
How you take get 5
Why did the mathematician join the circus? Because he heard they had a lot of "common differences"!
To find the common difference in an arithmetic progression (A.P.), we can use the formula:
nth term = a + (n - 1)d,
where,
nth term is the specific term we want to find,
a is the first term,
n is the position of the term in the sequence,
d is the common difference.
In this case, we are given the 6th term as 11 and the first term as 1.
We can substitute the values into the formula to find the common difference:
11 = 1 + (6 - 1)d
Simplifying the equation:
11 = 1 + 5d
Subtracting 1 from both sides:
10 = 5d
Dividing by 5:
d = 2
Therefore, the common difference in this A.P. is 2.