Calculate the number of mole calcium. That can be obtaine from 30g of calcium trioxocarbonate (iv) in the present of excess hydrocliod acid (ca =40, c =12, o =16, cl =35.5)
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how many moles of CaCO3 in 30g?
The reaction equation will tell you how many moles of CaCl2 to expect.
To calculate the number of moles of calcium that can be obtained from 30g of calcium trioxocarbonate (IV), we need to use the molar mass and balanced equation.
The chemical formula for calcium trioxocarbonate (IV) is CaCO3. In this compound, we have one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O).
To calculate the molar mass of calcium trioxocarbonate (IV), we need to multiply the atomic masses of each element by the number of atoms present and sum them up:
Molar mass of CaCO3 = (1 * Atomic mass of Ca) + (1 * Atomic mass of C) + (3 * Atomic mass of O)
= (1 * 40) + (1 * 12) + (3 * 16)
= 40 + 12 + 48
= 100 grams/mole
The molar mass of calcium trioxocarbonate (IV) is 100 grams/mole.
Now, we can use the molar mass and the given mass of calcium trioxocarbonate (IV) to calculate the number of moles:
Number of moles = Mass / Molar mass
Number of moles of CaCO3 = 30g / 100 grams/mole
Number of moles of CaCO3 = 0.3 moles
In the balanced equation for the reaction of calcium trioxocarbonate (IV) with hydrochloric acid, we can see that one mole of calcium trioxocarbonate (IV) will produce one mole of calcium chloride (CaCl2), along with carbon dioxide (CO2) and water (H2O).
Since the reaction occurs with excess hydrochloric acid, all the calcium trioxocarbonate (IV) will be consumed, and we will get one mole of calcium chloride.
Therefore, the number of moles of calcium that can be obtained from 30g of calcium trioxocarbonate (IV) is 0.3 moles.