calculate q when a system does 72g of work and its internal energy decrease by 90j
dE = q + w
72 g? of work? Is that (the g) a new unit?
If delta E decreases that means Efinal - Einitial is smaller which means energy is lost and that make the change -.
If the system does work then w is -. Substitute and solve. Post your work if you get stuck.
To calculate q (heat absorbed or released by the system), you need to use the equation:
q = ΔU + W
Where:
q is the heat absorbed or released by the system
ΔU is the change in internal energy of the system
W is the work done on or by the system
In this case, the system does 72g of work, so the work done on the system (W) is 72 g. However, we need to convert this to joules since work is typically measured in joules.
1 g = 0.001 kg
72 g = 0.072 kg
Given that the internal energy (ΔU) of the system decreases by 90 J, we can substitute these values into the equation:
q = -90 J + 0.072 kg
Therefore, q = -89.928 J (approximately)
To calculate q, the heat transferred in a system, we need to use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat transferred (q) plus the work done (w) on or by the system.
The formula for the first law of thermodynamics is:
ΔU = q + w
In this case, we are given that the internal energy (ΔU) of the system decreased by 90 J (joules) and the work done (w) on the system is 72 g (grams). However, work is not provided in the appropriate unit of joules.
To use the correct unit, we can convert grams to kilograms. Since 1 kg is equal to 1000 g, we have:
72 g = 72 g * (1 kg / 1000 g) = 0.072 kg
Now, we have the work done (w) in kilograms. To convert it to joules, we need to know the force (F) and the distance (d) over which the force is applied. Without this information, we cannot accurately determine the value of q.
Please provide the necessary information, such as the force and distance involved in performing the work, so we can calculate the heat transferred (q) using the first law of thermodynamics.