The surface area of a melting snowball decreases at a rate of 3.4cm2/min . Find the rate at which its diameter decreases when the diameter is 13cm . (Round your answer to three decimal places if required)
Ok - I'll do one more. Then it's time for you to step up and show some work.
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A = 4πr^2 = πd^2
dA/dt = 2πd dd/dt
-3.4 = 2π * 13 dd/dt
dd/dt = -3.4/(26π) cm/min