Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Algebra
Equations
X^x=27x^2. Find x
1 answer
hey - that's half a dozen you have posted like this.
Your turn to do some work.
You can
ask a new question
or
answer this question
.
Related Questions
Find all the zeros of the equation.
-3x^4+27x^2+1200=0 I know the zeros are –5, 5, –4i, and 4i, but how do I get there?
find all the zeros of the equation.
-3x^4+27x^2+1200=0 I'm really confused, can someone help explain?
I have a take home test and I'm stuck on a couple. Anyone help please?
1. Find the vertex & axis of symmetry: -5(x+4)^2-4 2. Find
[(6x+1)^3][(27x^2+2)-(9x^3+2x)](3)[(6x+1)^2](6) over [(6x+1)^3]^2
Help me simplify please? Here's what I got so far:
5. Solve using the elimination method. Show your work. If the system has no solution or an infinite number of solutions, state
Solve:
2log_3(x) - log_3(x-2) = 2 My Work: log_3(x^2) - log_3(x-2) = log_3(3^2) log_3 [(x^2) / (x-2)] = log_3(27) (x^2) / (x-2) =
Can you check the following questions,please?
Simplify 30. (-2y)^0/(3x^2)^-3 = 1/(3^-3)(x^-6) = 1/-27x^-6 = 27x^6 42.
Solve Ratio Problems with Proportions Quick Check2 of 5 2 of 5 ItemsQuestionWhich table represents a proportional
Express cube root 27x^4y^6 using rational exponents
(27x^4y^6)1/3 (27^1/3)(x^4/3)(y^6/3) stuck. I think the final answer is
If 3x+2y=12 and xy=6,find 27x^3+8y^3