14 6C→14 7N+ 0−1e
Which type of radioactive decay does the equation model?
gamma decay
beta-plus decay
beta-minus decay
alpha decay
Which is it? Perhaps I didn't do a very good job of explaining. It is beta minus. Did you have trouble understanding what I wrote?What could I have done better?
14 6C→14 7N+ 0−1e
It would make more sense if you write this (although icorrect) as
6C14 ==> 7N14 + -1e0
It's tough to write it correctly but the best I can do on the computer is this.
614C. The best way to make sense is this but it's not scientifically correct.
6C14. But to your problem. You're right. It is b or c. So what's keeping you from the decision? You could look on Google and it's easy to find exactly the charge and mass of beta plus and beta minus. You need to know what beta plus and beta minus are. It's easy enough. beta particles are electrons. That simple. So you write an e for electrons. Beta minus tells you the electron has a - charge and you know electrons have essentially no mass so a beta minues is a -1e0. That reads -1 charge, electron, zero mass. The beta plus is the opposite. It's +1e0.
Yeah I figured it was beta plus, I just wanted to double check.
Beta minus*
Well, let's see. We have the elements 6C and 7N, and an electron. It seems like we have some nuclear shenanigans going on here. Now, if we look closely, we can see that the number of protons is changing. That means it's a type of radioactive decay called beta decay, specifically beta-minus decay. So, my vote goes to beta-minus decay!
To determine the type of radioactive decay represented by the equation 14 6C → 14 7N + 0 −1e, we need to analyze the particles involved in the reaction.
In this equation:
- The element on the left side of the equation is carbon with an atomic number of 6 and a mass number of 14.
- The element on the right side of the equation is nitrogen, which has an atomic number of 7 and a mass number of 14.
- Additionally, an electron (e) with a charge of -1 is also part of the equation.
By examining the change in the atomic number and mass number, we can determine the type of radioactive decay that took place.
In this case, the atomic number increased from 6 to 7, indicating the emission of a positively charged particle. Since a beta particle (β) represents electrons or positrons (positively charged electrons), we see that a beta-minus decay occurred. This type of decay involves the conversion of a neutron into a proton, with the emission of an electron.
Hence, the type of radioactive decay modeled by the given equation is beta-minus decay.