calculate the mass percent composition of iron in K3[FeC2O4)3] x 3H2O. this is the theoretical % Fe in K3[Fe(C2O4)3 X 3H2O which assumes the K3[Fe(C2O4)3] x 3H2O is 100% pure
To calculate the mass percent composition of iron (Fe) in K3[Fe(C2O4)3] x 3H2O, you need to know the molar mass of Fe and the overall molar mass of the compound.
1. Find the molar mass of Fe:
The molar mass of Fe is 55.85 g/mol.
2. Find the molar mass of K3[Fe(C2O4)3] x 3H2O:
- The molar mass of K is 39.10 g/mol.
- The molar mass of C is 12.01 g/mol.
- The molar mass of O is 16.00 g/mol.
- The molar mass of H is 1.01 g/mol.
To find the molar mass of K3[Fe(C2O4)3] x 3H2O, you need to add up the molar masses of each element present and account for the number of atoms of each element in the formula.
- For K, there are 3 atoms: 3 * 39.10 g/mol = 117.30 g/mol
- For Fe, there is 1 atom: 1 * 55.85 g/mol = 55.85 g/mol
- For C, there are 6 atoms: 6 * 12.01 g/mol = 72.06 g/mol
- For O, there are 24 atoms: 24 * 16.00 g/mol = 384.00 g/mol
- For H, there are 6 atoms: 6 * 1.01 g/mol = 6.06 g/mol
Summing these up, you get:
117.30 g/mol (K) + 55.85 g/mol (Fe) + 72.06 g/mol (C) + 384.00 g/mol (O) + 6.06 g/mol (H) = 634.27 g/mol
3. Calculate the mass percent composition of Fe:
The mass percent composition of Fe can be calculated using the formula:
Mass Percent Composition of Fe = (Mass of Fe / Total Mass of Compound) * 100
Mass of Fe = Number of moles of Fe * Molar mass of Fe
To find the number of moles of Fe, consider the balanced chemical equation and the coefficient in front of Fe:
K3[Fe(C2O4)3] x 3H2O is written as K3[Fe(C2O4)3] x 3H2O, which means there is one mole of Fe for every one mole of K3[Fe(C2O4)3].
Hence, Number of moles of Fe = Number of moles of K3[Fe(C2O4)3]
Now, you can calculate the mass percent composition of Fe:
Mass Percent Composition of Fe = (Number of moles of Fe * Molar mass of Fe / Total Mass of Compound) * 100
Mass Percent Composition of Fe = (Molar mass of Fe / Total Molar mass of K3[Fe(C2O4)3] x 3H2O) * 100
Mass Percent Composition of Fe = (55.85 g/mol / 634.27 g/mol) * 100
Mass Percent Composition of Fe = 8.80%
Therefore, the mass percent composition of Fe in K3[Fe(C2O4)3] x 3H2O is approximately 8.80%.