The sum of two numbers is 51. The larger number is 5 more than the smaller number. What are the numbers?
y = x +5
y+ x = 51
so
x+5 + x = 51
2 x = 46
x = 23
y = 23 + 5 = 28
============
check
============
23 + 28 = 51
23 + 5 = 28. YES !
Well, well, well, it seems we have a little addition puzzle here. Let me put on my clown hat and solve it for you!
Let's call the smaller number "x" and the larger number "y". According to the information given, we know that y = x + 5.
Now, we also know that the sum of these two numbers is 51. So, we can write an equation: x + y = 51.
Substituting y with x + 5, we get x + (x + 5) = 51.
Simplifying that gives us 2x + 5 = 51.
Subtracting 5 from both sides, we have 2x = 46.
Finally, dividing both sides by 2, we find x = 23.
Now that we have x, we can substitute it back into y = x + 5. So, y = 23 + 5, which gives us y = 28.
So, the smaller number is 23 and the larger number is 28! Ta-daaa!
Let's denote the smaller number as 'x' and the larger number as 'y'.
According to the given information, we can translate the problem into two equations:
1. The sum of two numbers is 51: x + y = 51
2. The larger number is 5 more than the smaller number: y = x + 5
Now, we can substitute equation 2 into equation 1 to solve the system of equations:
x + (x + 5) = 51
2x + 5 = 51
2x = 51 - 5
2x = 46
x = 46 / 2
x = 23
Substitute the value of x into equation 1 to find y:
23 + y = 51
y = 51 - 23
y = 28
Therefore, the smaller number is 23 and the larger number is 28.
To find the numbers, let's assign variables to represent the two numbers. Let's call the smaller number "x" and the larger number "y".
According to the given information, we know that the sum of two numbers is 51. So, we can write an equation:
x + y = 51 -- Equation 1
We are also given that the larger number is 5 more than the smaller number. This can be expressed as:
y = x + 5 -- Equation 2
Now, we have a system of two equations with two variables. We can solve this system of equations using substitution or elimination.
Let's substitute Equation 2 into Equation 1:
x + (x + 5) = 51
Combining like terms:
2x + 5 = 51
Subtracting 5 from both sides:
2x = 51 - 5
2x = 46
Dividing both sides by 2:
x = 23
Now, substitute the value of x back into Equation 2:
y = 23 + 5
y = 28
Therefore, the smaller number is 23 and the larger number is 28.