At 50oC, the solubility of silver chloride, AgCl, is 5.2 x 10-4 g/100 mL. Calculate the Ksp at this temperature.

5.2E-4 g/100 mL= 5.2E-3 g/L

(AgCl) in mols/L = (0.0052 g/143.3 g/mol) = 3.62E-5 M
................AgCl ==> Ag^+ + Cl^-
I.................solid.........0.........0
C...........3.62E-5....3.62E-5...3.62E-5
E...............solid.....3.62E-5...3.62E-5
Ksp = (Ag^+)(Cl^-)
Plug the E line into the Ksp expression and solve for ksp.