A tennis ball with a speed of 29.4 m/s is moving perpendicular to a wall. After striking the wall, the ball rebounds in the opposite direction with a speed of 24.2844 m/s. If the ball is in contact with the wall for 0.0102 s, what is the average acceleration of the ball while it is in contact with the wall? Take “toward the wall” to be the positive
direction.
Answer in units of m/s
a = change in v / time
change in v = (24.2844 - 29.4) m/s
time = 0.0102 s
I suggest answering in m/s^2 not m/s