The point L(–4,–5) is rotated 90° counterclockwise around the origin. What are the coordinates of the resulting point, L'?
You did it wrong idiot
The point L(
–
4,
–
5) is rotated 90° counterclockwise around the origin. What are the coordinates of the resulting point, L'?
the answer is (5,-4)
he point J(5,3) is rotated 90° counterclockwise around the origin. What are the coordinates of the resulting point, J'?
To find the coordinates of the resulting point L', we need to rotate the point L(–4,–5) 90° counterclockwise around the origin.
To rotate a point counterclockwise around the origin by 90°, we can use the following formulas:
x' = x * cos(θ) - y * sin(θ)
y' = x * sin(θ) + y * cos(θ)
In this case, since we want to rotate the point 90° counterclockwise, we can use θ = 90°.
Substituting the given coordinates of the point L into the formulas, we have:
x' = -4 * cos(90°) - (-5) * sin(90°)
y' = -4 * sin(90°) + (-5) * cos(90°)
Now let's calculate each term:
cos(90°) = 0
sin(90°) = 1
x' = -4 * 0 - (-5) * 1
y' = -4 * 1 + (-5) * 0
Simplifying further:
x' = 0 + 5
y' = -4 + 0
Therefore, the coordinates of the resulting point L' are (5, -4).
The point L(
–
4,
–
5) is rotated 90° counterclockwise around the origin. What are the coordinates of the resulting point, L'?
The point T(
–
4,
–
1) is rotated 90° counterclockwise around the origin. What are the coordinates of the resulting point, T'?
what are you talking about this is the first one that I put in you may have the wrong person
Check Ella question below:
math
The point Z(–6,6) is rotated 270° counterclockwise around the origin. What are the coordinates of the resulting point, Z
ella
23 minutes ago
I t is originally 90+45 = 135 deg cc from the x axis
spin 270 more ----> 405 total
405 - 360 = 45
so 45 degrees above x axis in quadrant 1
(6, 6)
Anonymous