Calculate the percentage by mass of all the compound element of sodium trioxo(v) NaNO3
Na=23,N=14,O3=16
total mass = 23+14 + 3*16 = 85
now divide each element's mass share by the total * 100%
Note that sodium trioxo(v) NaNO3 is not the correct IUPAC name for NaNO3. An acceptable name is sodium nitrate. Tell us where you came up with that name; i.e., a reference will help a great deal.
To calculate the percentage by mass of each element in the compound sodium trioxo(v) nitrate (NaNO3), you need to determine the molar mass of each element and the molar mass of the entire compound.
The molar mass of an element is the mass of one mole (Avogadro's number) of atoms of that element.
Given:
- Na = 23 (molar mass of sodium)
- N = 14 (molar mass of nitrogen)
- O3 = 16 (molar mass of oxygen x 3 because there are three oxygen atoms)
Calculations:
- Molar mass of NaNO3 = (molar mass of Na) + (molar mass of N) + (molar mass of O3)
= 23 + 14 + (16 x 3)
= 23 + 14 + 48
= 85
Now, to determine the percentage by mass of each element:
- Sodium (Na):
- Mass of Na = molar mass of Na = 23 g
- Percentage by mass of Na = (Mass of Na / Molar mass of NaNO3) x 100
= (23 / 85) x 100
≈ 27.1%
- Nitrogen (N):
- Mass of N = molar mass of N = 14 g
- Percentage by mass of N = (Mass of N / Molar mass of NaNO3) x 100
= (14 / 85) x 100
≈ 16.5%
- Oxygen (O):
- Mass of O = molar mass of O3 = 16 x 3 = 48 g
- Percentage by mass of O = (Mass of O / Molar mass of NaNO3) x 100
= (48 / 85) x 100
≈ 56.5%
Therefore, the percentage by mass of sodium (Na) in NaNO3 is approximately 27.1%, the percentage by mass of nitrogen (N) is approximately 16.5%, and the percentage by mass of oxygen (O) is approximately 56.5%.