ax^3
_bx^2+cx_1÷ax^2+1 then f(-1)=1 abd f(2)=f(1)=2 then find the value of a,b and c
well, shoot, just plug in your numbers, and you get
(-a-b-c-1)/(a+1) = 1
(a-b+c-1)/(a+1) = 2
(8a-4b+2c-1)/(4a+1) = 2
Now just solve for a,b,c
_bx^2+cx_1÷ax^2+1 then f(-1)=1 abd f(2)=f(1)=2 then find the value of a,b and c
(-a-b-c-1)/(a+1) = 1
(a-b+c-1)/(a+1) = 2
(8a-4b+2c-1)/(4a+1) = 2
Now just solve for a,b,c