Solve log8-log4
your answer is log2
That is the whole idea.
To multiply a and b add their logs
To divide, subtract
log b/a = log b - log a
the reason is
base^log x = x
if the base is 10 then
10^log x = x
10^log y = y
so
x y = 10^log x + 10^log y = 10^(logx+ log y)
so
log xy = log x + log y
TYPO
x y = 10^log x * 10^log y = 10^(logx+ log y)
To solve the expression log8 - log4, we can use logarithmic properties.
First, recall the property of logarithms that states log(a) - log(b) is equal to log(a/b).
Using this property, we can rewrite the expression log8 - log4 as log(8/4).
Simplifying further, 8/4 equals 2. Therefore, log(8/4) equals log2.
Hence, the solution to log8 - log4 is log2.