net ionic equation for CoSO4.6H2O crystals are formed from solution after evaporation
[Co(H2O)6]^2+(aq) + [SO4]^2-(aq) ==> CoSO4(s).6H2O(s)
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To write the net ionic equation for the formation of CoSO4.6H2O crystals after evaporation, we need to identify the ions present in the solution and break down the compound into its constituent ions.
CoSO4.6H2O is cobalt (II) sulfate hexahydrate. When this compound dissolves in water, it dissociates into its constituent ions: cobalt (II) cations (Co^2+) and sulfate anions (SO4^2-).
The net ionic equation for the formation of CoSO4.6H2O crystals from the solution after evaporation can be written as:
Co^2+ (aq) + SO4^2- (aq) → CoSO4 (s)
In this equation, (aq) represents the aqueous state and (s) represents the solid state.
To determine the net ionic equation for the formation of CoSO₄·6H₂O crystals from a solution after evaporation, we need to consider the dissociation of the ionic compounds involved.
First, let's identify the ions present in the CoSO₄ compound. Cobalt(II) sulfate (CoSO₄) dissociates in water to form Co²⁺ and SO₄²⁻ ions.
CoSO₄ → Co²⁺ + SO₄²⁻
Next, let's consider the water molecules present in the crystal, represented by H₂O. These molecules do not dissociate and remain intact.
Now, we can write the overall equation for the formation of CoSO₄·6H₂O crystals after evaporation:
Co²⁺ + SO₄²⁻ + 6H₂O → CoSO₄·6H₂O
This equation shows that the Co²⁺ ions, SO₄²⁻ ions, and six water molecules combine together to form the CoSO₄·6H₂O crystals.
However, since there are no additional strong electrolytes or ions in the reaction, the net ionic equation is the same as the overall equation.