What volume of nitrogen react with 33.6 litre of oxygen to produced nitrogen dioxide
If the reaction is N2 + 2O2 --> 2NO2 is at STP, then
Then 33.6 L O2 x (1mol N2/2 mol O2) = 33.6 x 1/2 = ? L N2 @ STP
apostolic
33.6/22.4
what volume of nitrogen reacts with 33.6 litred of oxygen to produce nitrogen dioxide
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To determine the volume of nitrogen required to react with 33.6 liters of oxygen to produce nitrogen dioxide, we need to use the balanced chemical equation for the reaction and apply the principles of stoichiometry.
The balanced chemical equation for the reaction between nitrogen and oxygen to form nitrogen dioxide is as follows:
2 NO + O2 → 2 NO2
From the equation, we can see that 2 moles of nitrogen dioxide (NO2) are produced from 2 moles of nitrogen monoxide (NO) and 1 mole of oxygen gas (O2).
We need to convert the given volume of oxygen (33.6 liters) to moles using the ideal gas law, which states:
PV = nRT
Where:
P is the pressure of the gas (assuming constant)
V is the volume of the gas
n is the number of moles of the gas
R is the ideal gas constant
T is the temperature of the gas (assuming constant)
We can rearrange the ideal gas law equation to solve for n:
n = PV/RT
Now, substituting the given values:
P = constant
V = 33.6 liters
R = ideal gas constant
T = constant (assuming)
Let's assume the values of P, R, and T are constants for simplicity and leave them out of the equation:
n = 33.6 liters
Now, we know that 2 moles of nitrogen monoxide (NO) react with 1 mole of oxygen (O2) to produce 2 moles of nitrogen dioxide (NO2). Therefore, the ratio of nitrogen monoxide to oxygen is 2:1.
Since we have the number of moles of oxygen (n), we can calculate the number of moles of nitrogen monoxide required:
moles of NO = (2/1) * (n of O2)
moles of NO = 2 * 33.6 liters
Finally, using the ideal gas law once again, we can calculate the volume of nitrogen (N2) required. Since the number of moles of nitrogen (N2) is the same as the number of moles of nitrogen monoxide (NO), we can use the equation:
V = nRT/P
Substituting the known values:
n = moles of NO calculated previously
V = volume of N2 (to be determined)
R = ideal gas constant
T = constant (assuming)
P = constant
Simplifying the equation:
V = (moles of NO * R * T) / P
And inserting the values:
V = (2 * 33.6 liters * R * T) / P
Note: The R and T values can be ignored or assumed to be constants if the given data does not provide specific information about their values.
Thus, by substituting the given values and performing the necessary calculations, you can determine the volume of nitrogen required to react with 33.6 liters of oxygen to produce nitrogen dioxide.