1. f(x)=5x^2+x−3 and g(x)=7x^2−3x+8.
Compute the functions below.
(f+g)(x)=
(f−g)(x)=
(fg)(x)=
(fg)(x)=
2. f(x)=2x−3 and h(x)=2x−2.
(f+h)(−2)=
(fh)(−3)=
3.f(x)=4x+7 and g(x)=x^2−x.
(f∘g)(x)=
(g∘f)(x)=
not sure why you have (fg) twice, but I'll do a couple for you
(fg)(x) = f(x) * g(x) = (5x^2+x−3)(7x^2−3x+8)
now expand that out if you want
On the other hand
(f◦g)(x) = f(g(x))
f(g) = 5g^2+g−3 = 5(7x^2−3x+8)^2 + (7x^2−3x+8) - 3
see what you can do with the others. For ones with a value, you can do it two ways:
(fh)(-3) = f(x) * h(x) evaluated at x = -3
(fh)(-3) = f(-3) * h(-3)