A classroom has an area of (30x^3+8x^2) ft^2, with a width of 2x feet. What is the length of the floor?
P.S: I know the answer, but I don't know how to solve for it.
since width = area/length, you have
(30x^3 + 8x^2) / (2x) = 30x^3/2x + 8x^2/2x = 15x^2 + 4x
L w = 30 x^3 + 8 x^2
but w = 2 x
so
L = (30 x^3 + 8 x^2) / 2 x
= 15 x^2 + 4 x
Thank you!!
To find the length of the floor, we first need to understand the relationship between the area, width, and length of the classroom. The formula for the area of a rectangle is length times width (A = l * w). In this case, the width of the classroom is given as 2x feet.
So, we can set up an equation using the area and width:
Area = Length * Width
(30x^3 + 8x^2) = Length * (2x)
To solve for the length, we can divide both sides of the equation by 2x:
(30x^3 + 8x^2) / (2x) = Length
Now, we can simplify the equation by canceling out common factors and dividing each term by 2x:
(30x^3 / 2x) + (8x^2 / 2x) = Length
(15x^2) + (4x) = Length
Therefore, the length of the floor is 15x^2 + 4x feet.