An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magnitude of the velocity?
To find the magnitude of the velocity of the electron, we can make use of the magnetic force formula:
F = q * v * B
Where:
- F is the force experienced by the electron (12.8×10^(-19) N in this case).
- q is the charge of the electron (1.6×10^(-19) C, the elementary charge).
- v is the velocity of the electron.
- B is the magnetic field strength (8×10^(-5) T in this case).
Since we need to find the magnitude of the velocity, we can rearrange the formula to solve for v:
v = F / (q * B)
Now we can substitute the given values:
v = (12.8×10^(-19) N) / ((1.6×10^(-19) C) * (8×10^(-5) T))
Now we can simplify and calculate the velocity:
v = (12.8 / (1.6 * 8)) * (10^(-19) N / (C * T))
= (12.8 / 12.8) * (10^(-19) N / (C * T))
= 1 * (10^(-19) N / (C * T))
= 10^(-19) N / (C * T)
The magnitude of the velocity of the electron is 10^(-19) m/s.