Determine a power series for f(x)=6/(1+〖7x〗^4 ) and give the interval of convergence

Why did the power series go to school?

Because it wanted to expand its knowledge!

To find the power series representation of the function f(x) = 6/(1 + 7x^4), we can use the geometric series formula:

1/(1 - u) = ∑ (u^n)

where |u| < 1.

In this case, u = -7x^4, so we need |u| < 1 to ensure convergence:

|-7x^4| < 1
7x^4 < 1
x^4 < 1/7

Taking the fourth root of both sides gives us:

x < (1/7)^(1/4)

So the interval of convergence is (-((1/7)^(1/4)), ((1/7)^(1/4))).

Now, let's find the power series representation:

f(x) = 6/(1 + 7x^4)

= 6 * (1/(1 + 7x^4))

Substituting u = -7x^4, we have:

= 6 * ∑ (u^n)

= 6 * ∑ (-7x^4)^n

= 6 * ∑ (-7)^n * (x^4)^n

= 6 * ∑ (-7)^n * (x^4)^n

= 6 * ∑ (-1)^n * 7^n * x^(4n)

Therefore, the power series representation for f(x) is:

f(x) = 6 * ∑ (-1)^n * 7^n * x^(4n)

where the interval of convergence is (-((1/7)^(1/4)), ((1/7)^(1/4))).

To determine a power series representation for the function f(x) = 6/(1+7x^4), we can use the geometric series formula.

The geometric series formula states that for a series of the form 1/(1-r), the sum of the series can be expressed as a power series when |r| < 1.

In this case, our function f(x) can be written as 6 * (1/(1+7x^4)). We can rewrite 1/(1+7x^4) as a geometric series by noticing that the ratio between consecutive terms is (7x^4).

Now, we will substitute (7x^4) into the geometric series formula.

The formula for the sum of a geometric series is given by:

S = a/(1-r)

where
S is the sum of the series,
a is the first term of the series, and
r is the ratio between consecutive terms.

In this case, the first term a is 6 and the ratio r is 7x^4. Substituting these values into the formula, we get:

S = 6/(1-7x^4)

Simplifying further, we have:

S = 6 * (1 + 7x^4 + (7x^4)^2 + (7x^4)^3 + ...)

This is a power series representation of the function f(x), which converges for values of x such that |7x^4| < 1.

To find the interval of convergence, solve the inequality:

|7x^4| < 1

Divide both sides by 7:

|x^4| < 1/7

Take the fourth root of both sides:

|x|^(4/4) < (1/7)^(1/4)

Simplifying, we have:

|x| < (1/7)^(1/4)

So, the interval of convergence for the power series representation of f(x) is (-[(1/7)^(1/4)], (1/7)^(1/4)).