For decomposition of ammonium chloride to ammonia and hydrogen chloride at 427 degree Celsius and kp is 4.8 what is the value of kc
NH4Cl ==> NH3 + HCl
Kp = Kc(RT)^delta n
To find the value of Kc, we need to use the relationship between Kp and Kc.
The relationship between Kp and Kc for a gaseous reaction is given by the equation:
Kp = Kc(RT)^(∆n)
Where:
Kp is the equilibrium constant in terms of partial pressure
Kc is the equilibrium constant in terms of concentration
R is the ideal gas constant (0.0821 L·atm/mol·K)
T is the temperature in Kelvin
∆n is the difference between the sum of the moles of products and the sum of the moles of reactants
In this case, the given reaction is:
NH4Cl (s) ⇌ NH3 (g) + HCl (g)
Since the reaction involves a solid (NH4Cl), it is not included in the expression for Kc. Therefore, we only consider the gases NH3 and HCl.
The balanced equation shows that 1 mole of NH4Cl produces 1 mole of NH3 and 1 mole of HCl.
The difference in the sum of moles of products (1+1 = 2) and reactants (0) is ∆n = 2.
Now, we need to convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273
T(K) = 427 + 273
T(K) = 700 K
Substituting the values into the equation:
Kp = Kc(RT)^(∆n)
4.8 = Kc(0.0821)(700)^(2)
Simplifying the equation:
Kc = 4.8 / (0.0821)(700)^2
Using a calculator, we can evaluate the right-hand side of the equation to find:
Kc ≈ 0.00152
Therefore, the value of Kc for the decomposition of ammonium chloride to ammonia and hydrogen chloride at 427 degrees Celsius is approximately 0.00152.
To find the value of Kc for the decomposition reaction of ammonium chloride to ammonia and hydrogen chloride, we need to use the relationship between Kp and Kc. The equation relating Kp and Kc is given by the expression:
Kp = Kc(RT)Δn
Where:
Kp is the equilibrium constant in terms of partial pressures,
Kc is the equilibrium constant in terms of molar concentrations,
R is the ideal gas constant (0.0821 L·atm/(K·mol)),
T is the temperature in Kelvin,
Δn is the change in the number of moles of gas.
In the given reaction, ammonium chloride (NH4Cl) decomposes into ammonia (NH3) and hydrogen chloride (HCl):
NH4Cl(g) ⇌ NH3(g) + HCl(g)
From the balanced equation, we can see that the Δn, which is the change in moles of gas, is (1 - 1 - 1) = -1.
Given:
Kp = 4.8
To find Kc, we need the value of the temperature T in Kelvin. In this case, the temperature is stated as 427 degrees Celsius.
To convert Celsius to Kelvin, we use the equation:
T(K) = T(°C) + 273.15
T(K) = 427°C + 273.15 = 700.15 K
Now we have all the required values, we can substitute them into the equation:
Kp = Kc(RT)Δn
4.8 = Kc(0.0821 L·atm/(K·mol))(700.15 K)^(-1)
Simplifying,
4.8 = Kc(0.0821/700.15)
To find Kc, divide both sides by (0.0821/700.15):
Kc = (4.8) / (0.0821/700.15)
Kc ≈ 2826.5
Therefore, the approximate value of Kc for the decomposition of ammonium chloride at 427 degrees Celsius is 2826.5.