If you have 25 g N₂ and 25 g H₂ how many grams of NH₃ could you make?
N2 + 3H3 = 2NH3
This is a limiting reagent (LR) problem. You know that because amounts are given for more than one reactant.
You made a typo in the equation. I'm sure you meant to write
N2 + 3H2 = 2NH3
mols N2 = g/molar mass = 25/28 = 0.893
mols H2 = 25/2 = 12.5
mols NH3 produced with 25 g N2 and excess H2 = 0.893 mols N2 x (2 moles NH3/1 mols N2) = 01.78
mols NH3 produced with 25 g H2 and excess N2 = 12.5 mols H2 x (2 mols NH3/3 mols H2) = 8.33
In LR problems the smaller amount always wins since you may only produce the smallest amount of the product. The other reagent is the excess reagent. So N2 is the limiting reagent, you wil produce 0.893 mols NH3 and grams = mols NH3 x molar mass NH3 = ?
Post your work if you get stuck.
To find out how many grams of NH₃ you can make, you need to determine the limiting reactant. The limiting reactant is the one that will be completely consumed first, thus limiting the amount of product that can be formed.
First, we need to convert the given masses of N₂ and H₂ into moles. We can do this by using their respective molar masses. The molar mass of N₂ is 28 g/mol, and the molar mass of H₂ is 2 g/mol.
Number of moles of N₂ = 25 g / 28 g/mol
Number of moles of H₂ = 25 g / 2 g/mol
Next, we need to determine the stoichiometric ratio between N₂ and NH₃. From the balanced equation, we can see that the ratio is 1:2. This means that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.
Now, we can compare the number of moles of N₂ and H₂ to determine the limiting reactant. To do this, we divide the number of moles of each reactant by their respective stoichiometric coefficients:
Moles of NH₃ produced from N₂ = (Number of moles of N₂) * (2 moles of NH₃ / 1 mole of N₂)
Moles of NH₃ produced from H₂ = (Number of moles of H₂) * (2 moles of NH₃ / 3 moles of H₂)
The reactant that produces the smaller number of moles of NH₃ is the limiting reactant.
Finally, once we have determined the limiting reactant, we can calculate the number of moles of NH₃ formed and then convert it to grams using the molar mass of NH₃ (17 g/mol).
Mass of NH₃ = (Number of moles of limiting reactant) * (molar mass of NH₃)
By following these steps, you can determine the grams of NH₃ that could be formed.