If x is 12xy^2 7=? so if 12xy^2=x what is y. Y=z+129 z=394. Help!
umm... try something easier what school grade are you in?
damn is 4th grade hard now. I graduated and I have trouble with this one.
Assuming you don't have typos:
12xy^2=x divide both sides by 12x, y^2 = x/12x = 1/12x. What is the square root of 1/12x?
Y=z+129 z=394 then Y = 394+129 = ? I assume you can add those two.
Although delayed, I hope this helps.
12xy^2=x
12y^2 = 1 (for x≠0)
y^2 = 1/12
y = ±1/√ 12
To find the value of y in the equation 12xy^2 = x, we need to substitute the given values for x and solve for y.
Given:
12xy^2 = x
x = 7 (from the equation 12xy^2 = 7)
y = z + 129 (from the given equation y = z + 129)
z = 394
Substituting the value of x:
12xy^2 = 7
12(7)y^2 = 7
84y^2 = 7
Dividing both sides of the equation by 84:
y^2 = 7/84
y^2 = 1/12
Taking the square root of both sides:
√(y^2) = √(1/12)
y = ±√(1/12)
Now let's substitute the given value of z:
y = ±√(1/12)
y = ±√(1/12) = ±(1/√12) = ±(1/√(4*3)) = ±(1/2√3) = ±(√3/2√(3*3)) = ±(√3/6)
y = ±√3/6
So, the value of y is ±√3/6 or in decimal form approximately ±0.2887.