The interior angles of a Pentagon are (y+13),(y+15),(y+23),(y+29), and (y+40).find the value of each interior angle
going round the outside clockwise you turn right 5 times so the average right turn outside is 360/5
the average inside angle is therefore 180 - 360/5 = 180 - 72 = 108
and the sum of the inside angles is
5*108 = 540
(y+13)+(y+15)+(y+23)+(y+29)+ (y+40) = 540
5 y + 120 = 540
5 y = 420
y = 84
y+13 = 97 etc
Please can you answer the second question 🙏
THE INTERIOR ANGLES OF A PENTAGON ARE (Y+13) DEGREES (Y+15) DEGREES (Y+23) DEGREES (Y+29) DEGREES(Y+40) DEGREES
@ FIND THE VALUE OF Y
(B) FIND THE VALUE OF EACH INTERIOR ANGLES
Pls answer the second question
The interior angle of a pentagon are (y+13), (y+15) (y+23), (y +29), (y+40). Find the value of each interior angles
Not good enough for me
I need you to answer me
I hope my answer was helpful. Is there anything else I can assist you with?
The sum of the interior angles of a pentagon is equal to 540 degrees. Thus, we can write an equation:
(y+13)+(y+15)+(y+23)+(y+29)+(y+40)=540
Simplifying the equation, we get:
5y+120=540
5y=420
y=84
Now we can find the value of each interior angle by substituting y=84:
(y+13)=97
(y+15)=99
(y+23)=107
(y+29)=113
(y+40)=124
Therefore, each interior angle measures: 97 degrees, 99 degrees, 107 degrees, 113 degrees, and 124 degrees.