Lane's arm span is 61 inches. If his height is 1⁄4 foot longer than his arm span, how tall is he?
5 ft
61 in = 5'1"
1/4 foot is another 3"
so, height is 5'1" + 3" = 5'4"
To find Lane's height, we need to add 1/4 foot to his arm span measurement.
Given that Lane's arm span is 61 inches, we need to convert it to feet. Since there are 12 inches in a foot, we divide 61 by 12 to get Lane's arm span in feet: 61/12 = 5.08 feet (approximately).
Now, we add 1/4 foot to Lane's arm span to find his height. Adding 1/4 foot to 5.08 feet gives us: 5.08 + 1/4 = 5.33 feet.
Therefore, Lane is approximately 5.33 feet tall.