Question

5). At what temperature (K) will 0.854 moles of neon gas occupy 12.3 L at 1.95

atmospheres?

Answer 1

PV/nT is constant, so

1.95*12.3 / (273+T)*0.854 = 1*22.4 / 273*1

Answer 2

273+T = K, they asked for Kelvin