Before taking off, a plane travels at the speed of 1/4 km per second. The runway is 5km. How long does it take for the plane to get to the end of the runway?
Wow, 1/4 km/s on the runway????
that's 900 km/hour!
anyway ....
this superplane would reach the end of the runway in 5/(1/4) or 20 seconds
or
by ratios:
5/(1/4) = x/1
1/4 x = 5
x = 20
Who makes up these illogical questions.
A 747, one of the largest planes, needs a runway of 1.4 miles or about 2.4 km
Takeoff speed of a 747 is close to 300 km/h and that of a fighter jet is about 250 km/h
Well, let's do some math... but brace yourself for a little turbulence! If the plane is moving at 1/4 km per second and the runway is 5 km long, we can calculate the time it takes by dividing the distance by the speed. So, 5 km divided by 1/4 km per second... *drumroll please*... would take 20 seconds. That's pretty fast! Just keep in mind, this calculation doesn't account for any delays caused by the captain's indecisiveness or the flight attendants playing hide-and-seek with the beverage cart. Safe travels!
To find the time it takes for the plane to get to the end of the runway, we can divide the distance traveled by the speed.
Distance = 5 km
Speed = 1/4 km per second
Time = Distance / Speed
Plugging in the values:
Time = 5 km / (1/4 km per second)
To divide by a fraction, we can multiply by its reciprocal:
Time = 5 km * (4 km per second)
Now we can cancel out the units:
Time = 20 seconds
Therefore, it takes the plane 20 seconds to get to the end of the runway.
To find the time it takes for the plane to reach the end of the runway, you can use the formula: time = distance / speed.
The given speed of the plane is 1/4 km per second.
The distance of the runway is 5 km.
Plugging these values into the formula, we have:
time = distance / speed
= 5 km / (1/4 km/s)
To divide by a fraction, we can multiply by its reciprocal:
time = 5 km * (4 km/s)
= 20 seconds
Therefore, it takes the plane 20 seconds to get to the end of the runway.