How many grams of CuCl2 are required to make 75 ml of a 0.20M solution?
.075L * 0.20 mol/L = 0.015 moles of CuCl2
so how many grams is that?
To determine the amount of CuCl2 required to make a 0.20M solution of 75 ml, we need to use the formula:
Molarity (M) = moles/volume (L)
First, we need to convert the volume from ml to L by dividing it by 1000:
75 ml / 1000 = 0.075 L
Now, we can rearrange the formula to find the number of moles:
moles = Molarity x volume
moles = 0.20 M x 0.075 L
moles = 0.015 moles
Finally, we can use the molar mass of CuCl2 to convert moles to grams:
The molar mass of CuCl2 = (atomic mass of Cu) + 2 x (atomic mass of Cl)
= (63.55 g/mol) + 2 x (35.45 g/mol)
= 63.55 g/mol + 70.90 g/mol
= 134.45 g/mol
Now, we can calculate the grams of CuCl2:
grams = moles x molar mass
grams = 0.015 moles x 134.45 g/mol
grams = 2.0175 grams
Therefore, approximately 2.02 grams of CuCl2 are required to make 75 ml of a 0.20M solution.
To find the number of grams of CuCl2 required to make a 0.20M solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (L)
First, let's convert the given volume of solution from milliliters (ml) to liters (L):
75 ml = 75 / 1000 = 0.075 L
Now, rearrange the formula to solve for moles of solute:
moles of solute = Molarity (M) * volume of solution (L)
moles of solute = 0.20M * 0.075 L
Next, we need to convert moles of solute to grams using the molar mass of CuCl2. The molar mass of copper (Cu) is 63.55 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol.
The molar mass of CuCl2 can be calculated as:
(2 * molar mass of Cu) + (2 * molar mass of Cl) = (2 * 63.55 g/mol) + (2 * 35.45 g/mol) = 134.1 g/mol
Finally, calculating the grams of CuCl2:
grams of CuCl2 = moles of solute * molar mass of CuCl2
grams of CuCl2 = [(0.20M * 0.075 L) * 134.1 g/mol]
Now, calculate the final answer:
grams of CuCl2 = 2.01 grams (rounded to two decimal places)
Therefore, approximately 2.01 grams of CuCl2 are required to make a 75 ml of a 0.20M solution.