aluminum iodide and nickel are produced when aluminum and nickel (II) iodide react
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The reaction between aluminum and nickel(II) iodide can be represented by the following balanced chemical equation:
2 Al + 3 NiI2 → 2 AlI3 + 3 Ni
Here are the step-by-step details of the reaction:
Step 1: Write down the chemical formula of aluminum:
Al
Step 2: Write down the chemical formula of nickel(II) iodide:
NiI2
Step 3: Determine the reactants and products of the reaction:
Reactants: Aluminum (Al) and nickel(II) iodide (NiI2)
Products: Aluminum iodide (AlI3) and nickel (Ni)
Step 4: Balance the reaction equation by adjusting the coefficients to ensure that the number of atoms of each element is the same on both sides of the equation:
2 Al + 3 NiI2 → 2 AlI3 + 3 Ni
This equation shows that two moles of aluminum react with three moles of nickel(II) iodide to produce two moles of aluminum iodide and three moles of nickel.
To determine the products of a chemical reaction, we need to consider the chemical formulas and charges of the elements involved. In this case, we have aluminum (Al) and nickel (Ni) reacting with nickel (II) iodide (NiI2).
First, let's write out the chemical equation for this reaction:
Al + NiI2 → ??
To predict the products, we need to determine the charges of the elements involved. Aluminum typically forms Al3+ ions, while nickel can exist in various oxidation states. In this case, it is specified that nickel is in the +2 oxidation state, denoted as Ni(II).
Since we have an Al3+ cation and a Ni(II) anion (as part of NiI2), we need three Ni(II) ions to balance the charge of one Al3+ ion. This will allow us to produce two compounds: aluminum iodide (AlI3) and nickel (Ni).
Thus, the balanced chemical equation for the reaction becomes:
2Al + 3NiI2 → 2AlI3 + 3Ni
Therefore, aluminum iodide (AlI3) and nickel (Ni) are the products formed when aluminum and nickel (II) iodide react.