A rock is thrown upward with a speed of 48 feet per second from the edge of a cliff 400 feet above the ground. What is the speed of the rock when it hits the ground? Use acceleration due to gravity as -32 feet per second squared and approximate your answer to 3 decimal places. (10 points)
when does it hit?
400+48t-16t^2 = 0
and
v = 48 - 32t