A 2.55x10^-2kg silver ring is heated to a temperature of 84 degrees C and then placed in a calorimeter containing 5x10^-2kg of water at 24 degrees C. The calorimeter is not perfectly insulated, however, and 0.140kJ of energy is transferred to the surroundings before a final temperature is reached. What is the final temperature?

Question

A 2.55x10^-2kg silver ring is heated to a temperature of 84 degrees C and then placed in a calorimeter containing 5x10^-2kg of water at 24 degrees C.  The calorimeter is not perfectly insulated, however, and 0.140kJ of energy is transferred to the surroundings before a final temperature is reached.  What is the final temperature?

Anonymous · Answer

heat lost = 2.55*10^-2 * Csilver *(84-T) + 0.14*10^3 Joules heat gained = 5*10^-2 * Cwater * (T-24) heat lost = heat gained solve for T