A bus left Nairobi at 7am and travels towards Eldoret at 80km/h.At7.45am,a car left
i don't know how to do it
I don't know how to do it
Try reading what you typed and finish the question.
In any event if car 1 travels at speed 80 for x hours so 80 x km
then car 2 travels at speed s for (h - 3/4) hours so (h-.75) s km
80 x + (h-.75) s = distance from Nairobi to Eldoret
Question on a car left Nairobi at speed of 80km/ hr
To determine when the car catches up to the bus, we need to first calculate the distance between the two locations.
The bus has a head start of 45 minutes, which is equivalent to 45/60 = 0.75 hours. In this time, the bus would have traveled a distance of:
Distance = Speed x Time
Distance = 80 km/h x 0.75 h
Distance = 60 km
Therefore, the car needs to travel a distance of 60 km to catch up to the bus.
Now, let's assume the car's speed is "x" km/h.
Since both the car and the bus are traveling towards Eldoret, we can set up the following equation:
Distance covered by the car = Distance covered by the bus
x * t = 80t + 60
Where "t" represents the time it takes for the car to catch up to the bus.
We know that the car starts at 7.45 am, which is 45 minutes later than the bus. This can be written as t = (45/60) + t', where t' is the actual time it takes for the car to catch up to the bus.
Substituting the value of t into the equation, we get:
x * [(45/60) + t'] = 80[(45/60) + t'] + 60
Now we can solve this equation for t' to determine the time it takes for the car to catch up to the bus.